My dad mentioned this problem last night and he said he doesn't have the solution. Can you figure it out?
Three men go into a 7-11 and buy $30 worth of beer, paying $10 each. They leave but the store owner who took the cash realizes they overpaid by $5 since there was a special running. He gives his young employee 5 $1-bills and sends him after the men before they drive away. The boy runs out to the parking lot but figuring $5 is hard to split 3 ways, he decides to give them each $1 and keep the last $2 for himself (kids these days! sheesh!). So in the end, each man paid $9 for beer and the boy kept $2. The problem is, $1 disappears somehow in all this, because 3 x $9 = $27, and $27 (what the men paid) + $2 (what the boy kept) = $29. The store owner parted with $5 from the total of $30, leaving him with $25, with $5 gone with the boy, for a total of $30 on his side.
So what happened to the 30th dollar?
I have no idea what the answer to this is and as tempted as I am to Google for it, I want to see if someone else can figure it out first.
Three men go into a 7-11 and buy $30 worth of beer, paying $10 each. They leave but the store owner who took the cash realizes they overpaid by $5 since there was a special running. He gives his young employee 5 $1-bills and sends him after the men before they drive away. The boy runs out to the parking lot but figuring $5 is hard to split 3 ways, he decides to give them each $1 and keep the last $2 for himself (kids these days! sheesh!). So in the end, each man paid $9 for beer and the boy kept $2. The problem is, $1 disappears somehow in all this, because 3 x $9 = $27, and $27 (what the men paid) + $2 (what the boy kept) = $29. The store owner parted with $5 from the total of $30, leaving him with $25, with $5 gone with the boy, for a total of $30 on his side.
So what happened to the 30th dollar?
I have no idea what the answer to this is and as tempted as I am to Google for it, I want to see if someone else can figure it out first.
posted by Matt Campbell at 7:11 PM
4 Comments:
Each man paid $9 in to the shopkeeper and the boy(25 + 2 = 27). They each kept a dollar. (27+3 = 30). The trick being pulled is that $27 is the amount paid, whereas $2 is the amount kept(by the boy, specifically.) One is a negative value(the amount lost) and one is a positive value(the amount the boy has). Add them together, and you end up with $25 unaccounted for, not $1, and it is easy to see the amount of money missing is $25, which is easily attributed to the shopkeeper.
I got this from a friend via e-mail; I think this pretty much explains it:
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The men paid $30.
The store keeper said it was $5 too much.
The boy returned only $3, which means the total paid for the beer was $28 (25 + 3). The boy keeps $2. Described like that the math works.
Now...
Each man gets a dollar back from the 10 they paid. They've now paid $9 each for a total of $27. $27 + $3 = $30. The $2 the boy keeps doesn't figure into this equation, because it is not considered. It was not returned and thus is hidden within the total of $27.
So, now, Matthew, you just need to apply that much diligence to studying for your next Chem exam, and you will be golden! ;-) (Just teasing - Chem was so much harder than that!!)
So, now, Matthew, you just need to apply that much diligence to studying for your next Chem exam, and you will be golden! ;-) (Just teasing - Chem was so much harder than that!!).
*sigh*... yes...
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